Steve S. answered • 02/09/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
tan(ø)=-5/6 < 0 => Quadrant II or IV
cos(ø)>o => Quadrant I or IV
So ø lies in Quadrant IV
tan(ø)=-5/6 = y/x
triangle sides x,y,r : +6,-5,√(25+36)=√(61)
csc(ø)=r/y=-(√(61))/5
Seth B.
02/09/14