
Lorenzo P. answered 06/11/19
Senior Chemistry Student at UC Santa Barbara
First we must determine the the moles of KHC2O4 in the solution.
0.832 g KHC2O4 ÷ 128.125 g mol-1 = 0.00649 mol KHC2O4
We know every mole of KHC2O4 is titrated with one mole of NaOH, therefore we now know 0.00649 mol of NaOH were used to titrate the KHC2O4.
0.00649 mol NaOH ÷ 0.2580 L = 0.0252 M NaOH or 25.2 mM NaOH