J.R. S. answered 03/13/17
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AgNO3 + NaCl ==> NaNO3(aq) + AgCl(s) ... balanced equation
moles AgNO3 = 240 g AgNO3 x 1 mole/170 g = 1.41 moles AgNO3
moles NaCl = 200 g NaCl x 1 mol/58.4 g = 3.42 moles NaCl
AgNO3 is limiting, so moles moles AgCl and moles NaNO3 formed = 1.41 moles of each.
Not sure what the question asks, but you can subtract this number of moles from 3.42 moles NaCl to get the moles NaCl remaining, and then convert that to mass. There will be NO AgNO3 remaining as it was all used up.