calculate the mass of benzene required to produce 22g of co2 for reaction. 2C6H6+15O2->12 CO2+6H2O

Question

pls tell today itself

Answer 1

Hi Aslam,

 

The molar mass of CO₂ is 44g/mol.  If you produce 22g, that means you produce 22g/44g/mol = 0.5 mol of CO_2.

 

For 12 moles of CO₂, you need 2 moles of benzene.  Therefore, for 0.5 mol of CO₂, you will need 0.083 mol of benzene (0.5 mol divided by 6 since you need six times less benzene than CO₂).

 

The molar mass of benzene is 78 g/mol.  Therefore, 0.083 mol of benzene is 6.47 g (o.083 mol x 78 g/mol).

 

The answer is 6.47g of benzene is needed.

 

Hopefully, it helps.

Answer 2

This question is really just asking you to compare two things. The first thing I would do is look at the equation and realize that the ratio of benzene to carbon dioxide is 2:12, or simply 1:6. Now we need to convert the grams of Co2 they gave us to grams of benzene. We take the grams of CO2, divide it by its gram formula mass to get moles. Now use the mole ratio (1:6) to find moles of benzene. Basically set up an equation like: 1/6=x/moles of CO2 that you calculated. From there, just convert moles to grams and thats it, you're done!

Answer 3

The Molecular Mass (MM) of CO₂ is roughly 12+ 2(16) = 44 g/mol

So the number of moles of CO₂ needed would be 22g  / 44g/mol = 0.5 mol CO₂

Therefore, since the stoichiometric ratios of CO₂ : C₆H₆ are 12:2 then we need 1/6 the moles of benzene. 

We need 0.5/6 moles of benzene which has a MM of 6(12) + 6(1) = 78 g/mol

The mass of benzene needed would be 78 g/mol * 0.5/6mol = 6.5 g

 

I hope this helps!