
Rachel E.
asked 11/12/16Solve the following word problem.
The speed (in feet per second) of a ball tossed up in the air can be represented by the function v(t)=32|t|+5 where t is time in seconds. Based on this function, at what time would the speed of the ball be equal to 69 feet per second?
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1 Expert Answer

Arturo O. answered 11/12/16
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Rachel,
If no other information is available, I will just have to solve two different problems.
(1)
Assume you toss up and the positive direction is up.
v(t) = -32t + 5
If you want 69 ft/s in the up direction, there is no solution, because there is no positive t that makes
69 = -32t + 5.
A negative t is not appropriate because t = 0 is the moment the ball is tossed up at an initial speed of 5 ft/s. Before t=0, the ball was not in the state of motion described by the given equation. However, it can reach 69 ft/s on the way down, which is a velocity of -69 ft/s.
-69 = -32t + 5 ⇒ t = (-69 - 5)/(-32) s = 2.31 s
(2)
Assume you toss down and the positive direction is down.
v(t) = 32t + 5
69 = 32t + 5
t = (69 - 5)/(32) s = 2s
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Arturo O.
v(t) = -32t + 5
with v in ft/s and t in seconds.
If the ball is tossed down and down is the positive direction, then
v(t) = 32t + 5
The equation given in the problem statement describes a ball tossed down and accelerating downward, but the wording of the problem statement suggests a ball tossed up and accelerating downward. These are two different problems, and the solutions will be different. Please double check the wording of the problem and the given equation. I will be glad to help you once that is clarified.
11/12/16