Jesse K. answered 11/10/16
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Sin function
y= a sin(bx - c ) + d
where
a = amplitude
period = 2pi/b
horizontal shift =-c/b
vertical shift = d
Here given that
a = amplitude =3
period = 2pi/b
period = 2pi/b
6pi = 2pi/b
b=2pi/6pi
b=1/3
horizontal shift =-c/b
horizontal shift =-c/b
3pi/2 =-c/ 1/3
3pi/2 * 1/3 =-c
pi/2=-c
c=-pi/2
vertical shift = d
vertical shift = d
-1 =d
d=-1
substitute all value in our sin function equation
y= a sin(bx - c ) + d
y = 3 sin((1/3) x + pi/2 ) - 1
given that x= 2pi
y= 3 sin(1/3 * 2pi +pi/2)-1
= 3 sin (2pi/3 +pi/2)-1
= 3 sin(4pi/6 +3pi/6)-1
y = 3 sin(7pi/6) -1