Prashant K.

asked • 10/12/16

States of matter doubt

16g of oxygen at 37°C is mixed with 14 g of nitrogen at 27°C, the temperature of the mixture will be?

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Brandon J. answered • 10/12/16

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Prashant K.

Don't agree with your solution. Please re-read my question. Oxygen and nitrogen are not of equal amount. 
16g of oxygen and 14g of nitrogen
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10/12/16

Brandon J.

They aren't equal in mass, but they are equal in terms of moles. Both are diatonic elements meaning Oand N2. A mole of O has a mass of 32 g. The problem states the we have 16 grams. This means there is 0.5 moles of oxygen. 1 mole of Nitrogen, N2, has a mass of 28 g. If there 14 grams present then there is 0.5 moles of nitrogen. So the quantities are equal, and the temperatures will average out.  I overlooked them being diatonic earlier, however, the quantities, in terms of moles, are still equal.
 
If you have 50 ml of water at 30 degrees C and 50 ml of water at 40 degrees C, the resulting mixture would have a temperature of 35 degrees. Similar concept.
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10/12/16

Prashant K.

So...   the temperature of the mixture will be (37+27)/2 = 32C
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10/12/16

Brandon J.

Yup??????
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10/12/16

Brandon J.

Apparently Wyzant doesn't do emojis
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10/12/16

Prashant K.

Thank you Mr. Brandon
You're such a life saviour :)
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10/12/16

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