Solve the equation: x-2/x-6 = x+5/x-4

Question

Pls. show description of the full process 

Answer 1

This requires cross-multiplication. 

 

Given a/b = c/d (where neither b or d are equal to 0), then we have:

 

a * d = b * c, or ad = bc

 

Our problem becomes:

 

(x - 2)(x - 4) = (x - 6)(x + 5)

x² - 4x - 2x + 8 = x² + 5x - 6x - 30    by FOIL

x² - 6x + 8 = x² - x - 30

-6x + 8 = -x - 30

-5x + 8 = -30

-5x = -38

x = 38/5

 

Answer 2

Hi Maria

 

 

Just a note, going forward, please use parentheses to make your post clearer

 

I'm interpreting your post to be

 

x-2     x+5

---- = -----

x-6     x-4

 

but it can also be read as

x-(2/x)-6 = x+(5/x)-4

 

x-2     x+5
---- = -----
x-6     x-4

 

Begin by cross multiplying

 

(x-2)(x-4) = (x-6)(x+5)

 

Foiling each side, we have

 

x²-6x+8=x²-x-30

 

Rearrange terms, bringing all terms to the left 

-5x+38 = 0

5x=38

x = 38/5 = 7-3/5