Peter G. answered • 10/10/16

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The proof structure follows what it was in the last question. Here, as Kenneth S. says, except with variables matching my last answer rather than his answer above (my n+1 is his n, my n is his k), show that

(n+1)(4(n+1)

^{2}+6(n+1)-1)/3= n(4n

^{2}+ 6n - 1)/3 + (2n+1)(2n+3)*Hint:*use a common denominator of 3, and multiply everything out on both sides.

On the left is what is to be shown equal to what is on the right: the inductive hypothesis plus what is added to the sum in the inductive step.

Ian G.

10/10/16