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# log2x+log4x=2

Hi,
Not really sure how to solve this logarithm.

Log2x+log4x=2

Many thanks

### 4 Answers by Expert Tutors

Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
5.0 5.0 (3 lesson ratings) (3)
1
I would just add that x=2^(4/3)=2(2^(1/3))
so the simpler answer is x = 2 * cuberoot(2)
Kenneth G. | Experienced Tutor of Mathematics and StatisticsExperienced Tutor of Mathematics and Sta...
0
This problem becomes simple if you understand the meaning of logarithms, and recall some simple rules.

Note that by the log conversion formula, Log4x = Log2x/Log24, so the problem becomes

log2x(1 + 1/Log24) = 2,  so (1.5)log2x = 2 or  log2x = 2/(1.5) = 4/3,

Now remember, log2x = 4/3 means "the power that you raise 2 to in order to get x is 4/3", so x = the cube root of 24.

x = cube root of 16.

Many students become flustered when dealing with logarithms because they forget the meaning of the word logarithm.  I ask all my students repeatedly

Q: "WHAT IS A LOGARITHM?"    (At first, you will get a blank stare followed by....I dunno ;-)
A: A logarithm is an EXPONENT

Once students realize that the logarithm is simply the exponent of the base (b) the fear goes away

log10(100) is asking what the exponent of 10 is to produce 100....the exponent (logarithm) is '2'
Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...
4.8 4.8 (4 lesson ratings) (4)
-1
Log2 X + log 4 X = 2

log4 X= m     X = 4^m = 2 ^(2m )
Log 4 X = 2 log2 X

Log2 X +Log 4 X = Log2 X + 2 Log2 X = Log 2 X + Log 2 X^2 = Log 2 X^3 = Log 2 4

Log (X .X^2)2 = Log2 4

X^3 = 4

X = 3√4

Parviz,

If you substitute X = 2(2/3) in the original equation, you get 1 not 2.  X is the cube root of 16, not the cube root of 4 as you stated.
Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
-1
Hi Aimee;
log2x+log4x=2
We need to work with the same base.
Let's convert one base.
I select the base of 4 because 22=4...
log4x
(log2x)/(log24)
(log2x)/2
(1/2)log2x
The equation is now...
log2x+(1/2)log2x=2
Let's combine like terms...
(3/2)log2x=2
Let's multiply both sides by 2/3...
log2x=4/3
x=24/3
The position of 3 in the denominator of the exponential means this is a cube root...
x=cube root(24)
x=cube root(16)