Joyce H. answered 09/25/16
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Home School Math Teacher and Tutor
Note event A may be included inside event B, or they may just overlap. The minimum value for P(A∪B) is 2/3 and occurs when event A is included inside event B. The maximum value for P(A∪B) is 1, because probabilities cannot be greater than 1, and occurs when event A overlaps event B.
P(A|B) = P(A∩B) / P(B)
So you need to find P(A∩B).
P(A∩B) = P(A) + P(B) - P(A∪B)
Two cases as discussed above:
P(A∩B) = 1/2 + 2/3 - 2/3 = 1/2 (when event A is included inside event B)
or
P(A∩B) = 1/2 + 2/3 - 1 = 1/6 (occurs when event A overlaps event B)
Using the two cases:
Maximum: P(A|B) = P(A∩B) / P(B) = (1/2) / (2/3) = 3/4
Minimum: P(A|B) = P(A∩B) / P(B) = (1/6) / (2/3) = 1/4