Hi Lisa;
f(x)/g(x)
(x^{2}1)/(x1)
x cannot equal 1 because this would render the denominator, also known as the divisor, as zero.
x can be greater than 1.
If you would like, we can factor the numerator...
x^{2}1
(x+1)(x1)
FIRST...(x)(x)=x^{2}
OUTER...(x)(1)=1x=x
INNER...(1)(x)=1x=x
LAST...(1)(1)=1
x^{2}x+x1
x^{2}1
So...
f(x)/g(x)=[(x+1)(x1)]/(x1)
(x1) is in the numerator and denominator. It cancels...
f(x)/g(x)=(x+1)
1/12/2014

Vivian L.