Math problem

Question

The half-life of radioactive (²²⁶Ra) is about 1599 years. That is, for a given amount of radium, half of the original amount will remain after 1599 years. After another 1599 years, one-quarter of the original amount will remain, and so on. Let y represent the mass, in grams , of a quantity of radium. The quantity presents after t years, then is...

 

y=25(1⁄2)^t⁄1599

 

How much is the initial mass is present after 2500 years?

 

Answer 1

Y =25(1/2)^(2500/1599)

 

just use a scientific calculator

to  get the answer