Mark M. answered 09/06/16
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Retired math prof. Very extensive Precalculus tutoring experience.
(a). Substituting 7 into the equation yields log(-10) + log(-10) = 2. Since the logarithm of a negative number is undefined, 7 is not a solution of the equation.
(b). log((x+3)(x-8)) + log((x+3)/(x-8)) = 2
log[(x+3)(x-8)(x+3)/(x-8)] = 2
log(x+3)2 = 2
Converting to exponential form, we get (x+3)2 = 102 = 100
So, x+3 = ±10
x = 7 or x = -13
We know from (a) that 7 is not a solution. Checking -13 in the original equation shows that -13 is a solution.
The only solution is -13.