Search
Ask a question
0 0

Find all solutions in the interval [0,2pi): sin2x=cosx

This is for my trig class, thanks for the help! If you could, could you please show all your work? Thanks again!
Tutors, please sign in to answer this question.

1 Answer

 Sin 2X = CosX
 
  2 Sinx CosX - CosX =0
 
    CosX ( 2 Sin X - 1 ) =0
 
   Cos X = 0      X = 90° = π/2     or X = 270° = 3π/4
 
 
     2SinX = 1       X = 30° = π/6  or  X = 150° = 5π/6