Solve for y

Question

|6y-3|+8=35

 

Solve for y

Answer 1

First thing you need to do is get that absolute value by itself, so we need to subtract 8 from both sides.

 

|6y-3|+8=35

 

|6y-3|=27

 

The stuff inside the absolute value bars could be equal to 27 or -27, because both |27|=27 AND |-27|=27. This means we need to split the problem into two different equations and solve both.

 

6y-3= 27      AND      6y-3= -27

 

6y=30          AND      6y= -24

 

y=5              AND       y=-4

 

Please let me know if you have any questions.

 

Answer 2

|6y-3|+8=35

|6y-3| = 27

 

The absolute value of |6y-3| has either the value (6y - 3) or -(6y - 3), which ever of these is positive.

 

If |6y-3| = 6y - 3, then 6y - 3 = 27 and y = 5

If |6y-3| = -(6y -3) = 3 - 6y, then 3 - 6y = 27 and y = -4

 

Then y = 5 or y = -4

Answer 3

⌈6x - 3⌉ + 8 = 35

 

      ⌈6x - 3⌉ = 27

 

-27 = 6x -3 = 27

+3         +3   +3

 

-24 = 6x = 30

÷6    ÷6     ÷6

 

-4 =x =36

 

x = -4, 36