Kyle,
The difficulty with this question is that you see two logarithms with different bases. Remember that ln is loge and log is log10. What you must do is write one of these in terms of the base of the other logarithm. Since e is the base most used in advanced math (calculus, etc.), I will show you how to do this using ln only.
Remember the Change of Base formula:
logbx = (logax)/(logab).
If you don't know already, the idea is to compute (or rewrite) logbx in terms of loga. Here, you would use b = 10 and a = e. Thus,
log x = (ln x)/(ln 10).
When you go back to the original equation and replace log(x) by this, you get the new equation.
ln x − (ln x)/(ln 10) = 1.
To solve for x, you must first gather all ln x terms together and factor it out from them:
(ln x)(1 − 1/ln 10) = 1.
You can next divide by the second factor on the left side of the equation:
ln x = 1/(1 − 1/ln 10).
Although this looks a little messy, you can simplify it by getting the denominator (under the 1) on the right rewritten with a common denominator.
1 − 1/ln 10 = (ln 10 − 1)/(ln 10).
You can then take its reciprocal by flipping the fraction upside down:
ln x = (ln 10)/(ln 10 − 1).
Now, to solve for x, you exponentiate both sides. That means, raise e to both sides and set the results equal to each other.
x = eln x = exp [(ln 10)/(ln 10 − 1)].
As for simplifying the answer, you can use a calculator and get x ≈ 1.7677. Due to the exponent being a fraction, there is no easy way to simplify the answer to be put in an exact form.
Kyle R.
07/17/16