(x+3)·loga(ax) = x
Now loga(ax) = x, so we have:
(x+3)·x = x
x2 + 3x = x
x2 + 2x = 0
x(x+2) = 0
which is true for x = 0 and -2
Alex C.
asked • 07/16/16Logs, solving for x
(x+3) loga a^x = x
Sorry that its small.
Follow
•
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
