Logs, solving for x

Question

(x+3) log_a ^{a^x} = x 

 

 

 

Sorry that its small. 

Answer 1

(x+3)·log_a(a^x) = x

 

Now log_a(a^x) = x, so we have:

 

(x+3)·x = x

 

x² + 3x = x

 

x² + 2x = 0

 

x(x+2) = 0

 

which is true for x = 0 and -2