how would I solve this equation 14x^2 + 19x - 3 = 0

Question

i have problems with equation I need help.

Answer 1

There are two ways:

 

1) Factor the left side using FOIL.  Then set the two factors equal to zero to solve for the two x values.

 

2) Use the quadratic formula (only when factoring is not possible).

 

    x = (-b ± √(b² - 4ac)) / 2a

 

    where:

    a = 14

    b = 19

    c = -3

Answer 2

Hey Francine,

There multiple ways of solving quadratic equations ( Degree 2 )

one way is to factor.

I'm gonna apply what is known as AC method!

Take 14 multiply it by 3

14×-3=-42

now we will look at the factor of - 42 that add up to 19

such number are 21 and -2

now we will split the 19x into 21x-2x

so we have 14x^2-2x+21x-3=0

by grouping we have 2x(7x-1)+3(7x-1)=0

7x-1 is common factor we can factor it out

we get (7x-1)(2x+3)=0

so 7x-1=0 or 2x+3=0

x=1/7 or x=-3/2

hope that helps