what will be the volume of hydrogen liberated at standard conditions when sulfuric acid chemically acts on 120 gramof metallic magnesium :

Question

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Answer 1

The balanced equation for this reaction is

Mg + H₂SO₄ --> MgSO₄ + H₂↑

 

The amount of magnesium is 120g which is 120g/mole ÷ 24g = 5 moles

 

That fact means that 5 moles of hydrogen gas will be produced.

 

The volume of one mole of hydrogen gas is 22.4l.

So, the total gas volume will be 22.4L/mole x 5 moles = 112L at standard temperature and pressure.