A. (-8, 5) B. (8, -5) C. (-8,-5) D. (8,5)

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y + 5 = 2(x + 8)

=> distribute the 2 on the right hand side of the equation into each term inside the parentheses to get:

y + 5 = 2x + 16

=> subtract 5 from both sides of the equation to get:

y = 2x + 11

Now that you have the equation in this form (slope-intercept form) it is easy to rule out choices B and D since the x-coordinate for each of these points is 8 and so the right hand side of the equation will be 27 which obviously does not equal 5 or -5.

For choice A, we have that x=-8 and y=5. So we get

5 = 2(-8) + 11 ==> 5 = -16 + 11 ==> 5 ≠ -5

For choice C, we have that x=-8 and y=-5. From the calculation from choice A, we that -5 = -5.

Thus, the point that lies on the line with the slope-intercept form y = 2x + 11 is choice C (-8, -5).

Tom D. | Very patient Math Expert who likes to teachVery patient Math Expert who likes to te...

Two ways to do it

1)Brute force plug & chug all candidates (never fails)

2)Better way: Note that a point is the "zeros" of each side

ie (x+8), (y+5) -----> (x,y)=(-8,-5)

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