Kylie H.

asked • 05/23/16

Current in a resistor? Resistance?

a. What is the current in a 40.0 Ω resistor that has a voltage drop of 14.0 V across it?

b. What is the equivalent resistance of a 3.0 Ω resistor, a 6.0 Ω resistor, and a 4.0 Ω resistor connected in parallel?

1 Expert Answer

By:

Alan G. answered • 05/23/16

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Kylie H.

Thank you for the equations! I am not sure if a voltage drop simply means that is the voltage or if a 40.0Ω resistor means that 40 is the voltage but that's what I did:
 
V=IR
14=I(40)
I=2.86
 
1/R= (1/3)+(1/6)+(1/4)
(4/12)+(2/12)+(3/12)=9/12=(1/1.3)
 
Please let me know if I did these right.
 
Thank you
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05/24/16

Alan G.

Kylie,
 
Actually, the value for I you found is wrong. If I=14/40, it could not be 2.86 Amperes. You must recompute this.
 
As for the second question, the right side of the formula simplifies to 3/4, which means the equivalent resistance is 4/3=1.33 Amperes. Your work is ok, you just didn't finish stating the answer.
 
The idea behind a resistor is to impede the flow of electric current through it. This results in a voltage drop proportional to the current with the resistance as the proportionality constant. Voltage is measured in volts, resistance in ohms, and current in amperes.
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05/24/16

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