Joshua Psalms T. answered 05/14/16
Tutor
5
(5)
Civil EIT, Former College Professor of Mathematics (in Asia)
When two sides are given and an included angle (an angle between the two given sides). Your only choice is to use Cosine Law:
c2 = a2 + b2 -2abCosC (Remember, the a, b and c here are now fixed, it depends on which 2 given sides are given and which included angle)
Using the equation:
c2 = 62 + 42 -2(6)(4)cos96
c2 = 57.0174
c = 7.551
From here, it's better to use Sine Law to get the remaining angles:
(sinA)/a = (sinB)/b = (sinC)/c
Let's use (sinA)/a = (sinC)/c
(sinA)/6 = (sin96)/7.551
sinA = 0.7902
A = Sin-10.7902 = 52.208º
To get B, either repeat the process above, using (sinB)/b or you could just add the three angles with the sum of 180.
A + B + C = 180
52.208 + B + 96 = 180
B = 31.792º