part 1 the equation for this equilibrium is Ag2SO4 ⇔ 2Ag+ + SO4-
the atomic weight of silver sulfate is 2Ag (107.86) + S (32.06) + O(16•4) = 311.78
we have 4.86g = 4.86/311.76 = 0.0156 mols
the concentration of Ag+ = 2(0.0156) = 0.0312mols, and SO4- = 0.0156
so, the solubility constant is Ksp = [Ag+]2[SO4-]
we get Ksp = [0.0312]2[0.0156] = 0.000974•0.0156
Ksp = 0.0000151 = 1.51x10-5
part 2 According to text I have entitled the "Principles of Chemistry", there is generally no good way to predict how the solubility will vary with temperature.
If your text or teacher has a different view, I will be interested to know what it is.