Can you please help me solve this problem> If each of the dimensions of a rectangle is increased by 100% , by what percent is the area increased.

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There is an important difference in the ways the new area could possibly be stated.

The new area is 4 times what it was before.

2L x 2W = 4LW

So the new area is four times the old area of LW

or 400% of the old area.

But the increase in area is 300%

Increase is looking for the difference between the old and new.

4LW - LW = 3LW increase

So the increase in area is 3 times what the old area was

or the increase in area is 300%.

Since according to your question you are asked for the percent increase,

the answer would be "the area is increased by 300 precent".

100% = 1

A = length * width

"... if each of the dimensions of a rectangle is increased by 100% ..."

Let length of new rectangle be "l_{1}" and width - "w_{1}"

l_{1} = l + l * 100% = l + l * 1 = 2l

w_{1} = w + w * 100% = w + w * 1 = 2w

A_{1} = 2l * 2w = 4lw =

lw + 3lw =

A = length * width

"... if each of the dimensions of a rectangle is increased by 100% ..."

Let length of new rectangle be "l

l

w

A

lw + 3lw =

A + 3A =

A +

Thus,

Hi Juanelle;

Increasing anything by 100% is doubling it.

Area=(length)(width)

4(Area)=[2(length)][2(width)]

4=2x2

Let's try a hypothetical example.

A rectangle is 4 units x 3 units.

Its area is 12 units-squared.

We will increase both dimensions by 100%. We will double each of these.

It is now 8 units x 6 units.

Its area is 48 units-squared.

Its increase is 4x^{2}=(2x^{2}+2x^{2})

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