Mark M. answered 04/26/16
Tutor
4.9
(952)
Retired Math prof with teaching and tutoring experience in trig.
An equation of the circle with center (h,k) and radius r is (x-h)2+(y-k)2=r2
So, we have (x+2)2+(y-2)2=81
Since (7,m) is on the circle, (7+2)2+(m-2)2=81
81 + (m-2)2=81
(m-2)2=0
m = 2