Tim T. answered 06/01/19
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Yes! Lets solve this shall we ?
So, we must use the Law of Sines to find the other values angle C, side a and side b. Then,
sin117 / a = sin45 / b = sin18 / 14 ..........Because C = 180 - (117 + 45) = 18. We can now solve for side b first such that
sin45 / b = sin18 / 14..............Cross multiply such that
bsin18 = 14sin45............Now divide sin18 such that
b = (14sin45 / sin18)
b = 32.04
Then, we solve for a such that
sin117 / a = sin45 / 32..............Cross multiply such that
asin45 = 32sin117.............Then divide sin45 such that
a = (32sin117 / sin45)
a = 40.32
I hope this helped!