Tim T. answered 06/01/19
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Great! Lets solve this shall we ?
So, we must solve this problem using the Law of Sines! We can begin by solving for a first be setting the equation equal to,
sin23.3 / a = sin52.9 / 2.24................Cross multiply to obtain
asin52.9 = 2.24sin23.3.......................Then divide sin52.9 such that
a = (2.24sin23.3 / sin52.9)
a = 1.11
Note: that angle B is 180 - (52.9 + 23.3) such that B = 180 - 76.2 = 103.8. Now we can solve for side b such that
sin23.3 / 1.11 = sin103.8 / b...............Cross multiply again such that
bsin23.3 = 1.11sin103.8..............Then divide sin23.3 such that
b = (1.11sin103.8 / sin23.3)
b = 2.73
I hope this helped!