x-1, x, and x+1 are the integers

x-1+x+x+1=-9

3x=-9

x=-3

x-1=-4

x+1=-2

-2, -3, and -4

or you can do the following...

find the mean of the three integers; this will be the middle integer

-9/3=-3

-3-1=-4

-3+1=-2

Alexis H.

asked • 04/21/16I am trying t find ingtegers of numbers

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x-1, x, and x+1 are the integers

x-1+x+x+1=-9

3x=-9

x=-3

x-1=-4

x+1=-2

-2, -3, and -4

or you can do the following...

find the mean of the three integers; this will be the middle integer

-9/3=-3

-3-1=-4

-3+1=-2

Dean J. answered • 04/21/16

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a + b + c = -9

where a is the first number

where b = a +/- 1 => given that the number is negative b = a - 1

where c = a +/- 2 => given that the number is negative c = a - 2

Therefore a + (a - 1) + (a - 2) = -9 => 3a - 3 = -9 => 3a = -6 => a = -2

From this we can conclude that b = -3 and c = - 4

Therefore we have three consecutive number = -9

Hope this helps.

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