tan^2 60degrees + sec 30degrees x sin 45degrees

Question

Hi, I'm having trouble finding the exact value. My difficulty is in the part where you add and multiply. Can you help me with steps?

Answer 1

Find tan 60^o (it's square root of 3--think about the 30-60-90 triangle having hypotenuse 2, short leg 1, long leg √3)

 

Using same triangle, find cos 30^o--it's ½√3; take reciprocal to get sec 30^o.

 

Surely you know that sin 45^o = ½√2 or just 1/√2.  These remarks are the "steps" that you request.

 

So you have all numbers that you need to work with...

 

Since you're in a trigonometry/Algebra II course, I assume that you can do the substitution, squaring, multiplying stages.  Remember that you can check this using a calculator, too.