x^2=y^2=13 and x^2-y^2=5

Question

solve the following system of equations please help

Answer 1

I think I know what he meant.

x^2 + y^2 = 13

x^2 - y^2 = 5


y^2 = 13 - x^2


Substitute:
x^2 - (13-x^2) = 5

x^2 - 13 + x^2 = 5

2x^2 - 13 = 5
2x^2 = 18

x^2 = 9

x = +- 3

Plug it back in:
x^2 + y^2 = 13
3^2 + y^2 = 13

9 + y^2 = 13

y^2 = 13-9 = 4

sqrt(y^2) = sqrt(4)

y = +/- 2

Answer:

( 3, 2 ) ( 3, -2 )
( -3, 2 ) ( -3, -2 )