
Thomas E. answered 04/07/16
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Tom E., a Patient and Knowledgeable Mathematics Tutor for You
The acceleration due to gravity is -32 ft/sec. The position of the dog can be shown by:
4t + 1/2(-32)t2 where t is time in seconds simplified:
-16t2 + 4t
Too find when he hits the ground set the equation = 0 and solve for t
-16t2 + 4t = 0
-4t(4t - 1)=0 which occurs at time 0 (when the dog first leaps) and again 1/4 when he hits the ground