Roman C. answered 04/04/16
Tutor
5.0
(851)
Masters of Education Graduate with Mathematics Expertise
Let y = x - 1.
Then 3x/(2 - x) = (3y + 3)/(1 - y) and the latter is to be written as a power series centered at 0.
(3y + 3)/(1 - y) = -3 + 6/(1 - y)
Use the geometric series to get
-3 + (1 + y + y2 + y3 + ...) = -2 + y + y2 + y3 + ... = -2 + ∑n=1,...,∞ yn
So the original expression's power series centered at 1 is
3x/(2 - x) = -2 + ∑n=1,...,∞ (x - 1)n
Douglas N.
In my comment above,
3x/(2-x) = -2 + ∑n>=16(x - 1)n
should be
3x/(2-x) = 3 + ∑n>=16(x - 1)n
Report
04/04/16

Roman C.
tutor
Thanks for the correction. I rushed because there was only a short time window for me at that moment.
You are right that we should report a convergence interval.
Report
04/06/16
Douglas N.
04/04/16