Bill K. answered 03/27/16
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Ivy League College Prep
Given the standard deviation of the normally distributed population is 1125, we can calculate the sample error as:
1125/sqrt(n) where n=20 is the sample size. This suggest that the standard error is 251.
Given this standard error a measurement of $5180 would be $670 from the mean or 2.66 standard error smaller than the mean. This is rather unusual. The probability of this occurring by chance is less than 0.4%.
https://en.wikipedia.org/wiki/Standard_normal_table