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this is a half angle problem... let sinx=-1/3 with x in Quadrant III evaluate sinx/2

please I need help I don't know how to solve this!!!!!!
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1 Answer

x/2 is in quadrant 2. Therefore,
cos(x) = -sqrt(8)/3,
sin(x/2) = sqrt[(1/2)(1-cosx)] = sqrt[(1/2)(1+sqrt(8)/3)]