In a triangle, the measure of one angle is 50 degrees. the measure of the second angle is 30 degrees more than the measure of the third angle. Find the measures of the second and third angles.

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Hi Chris;

FIRST...50

SECOND...x+30

THIRD...x

TOTAL...180

You probably already know that the total degrees of all angles of a triangle is 180.

180=(50)+(x+30)+(x)

180=50+x+30+x

Let's combine like terms...

180=80+2x

Let's subtract 80 from both sides as we proceed to isolate x...

-80+180=80+2x-80

100=2x

Let's divide both sides by 2...

100/2=(2x)/2

50=x

THIRD...50

SECOND...50+30=80

FIRST...50

Let's check our work...

180=50+80+50

180=180

50 + (30 + x) + x = 180

80 + 2x = 180

2x = 180 - 80

2x = 100

x = 50

first angle: 50

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