
Tim M. answered 03/06/16
Tutor
5
(2)
Statistics and Social/Biological Sciences
Hi Shawna,
This type of problem is usually solved with a binomial test.
The formula for this test is:
(X - p)/sqrt(p*q/n), where X is the proportion of times the theory worked, p is the proportion of times we expect it to work by chance, q = 1 - p, and n is the number of years that you tested the theory.
The first thing we have to do is compute proportion for the number of times it worked:
It worked 23 out of 34 times: 23/34 = .676471
Since we know the theory is false, we would it to work only 50% o the time or 0.5.
So the numerator of the formula becomes: .676471 - .5 = .176471
For the denominator, we know p. q is 1 - p = .5.
n is just the number of times you tested the theory, in your case, 34.
So the denominator is sqrt(.5*.5/34) = .085749
Now we find .176471/.085749 = 2.057983
This type of problem is usually solved with a binomial test.
The formula for this test is:
(X - p)/sqrt(p*q/n), where X is the proportion of times the theory worked, p is the proportion of times we expect it to work by chance, q = 1 - p, and n is the number of years that you tested the theory.
The first thing we have to do is compute proportion for the number of times it worked:
It worked 23 out of 34 times: 23/34 = .676471
Since we know the theory is false, we would it to work only 50% o the time or 0.5.
So the numerator of the formula becomes: .676471 - .5 = .176471
For the denominator, we know p. q is 1 - p = .5.
n is just the number of times you tested the theory, in your case, 34.
So the denominator is sqrt(.5*.5/34) = .085749
Now we find .176471/.085749 = 2.057983
This value is a z-score which we can use to find the probability. To do so, we need to use a normal distribution table (your teacher should have given you one or there should be one in your book). If we look up 2.057983 in the table, we find the value 0.019796. This number is the proportion of times you would expect the theory to work 23 or more times out of 34 tries (in other words, this should occur 1.9796% of the time).
Hope that helps.