A player shoots a basketball from a height of 6 feet.

Question

A player shoots a basketball from a height of 6 feet. The equation, h = -16t 2 + 25t + 6, gives the height, h , of the basketball after t seconds. Describe the height, rounded to the nearest tenth of a foot, of the basketball after 1.5 seconds, assuming no other player touches the ball.

 

_ feet above the ground

 

im so confused

 

Answer 1

So in this equation, the variable h represents the height of the ball after a certain amount of time, with time being represented with the variable t.

 

h = -16t² + 25t + 6

 

So to find h after 1.5 seconds, we simply plug in 1.5 for t:

 

h = -16(1.5²) + 25(1.5) + 6     Square the first 1.5, and multiply 25*1.5

h = -16(2.25) + 37.5 + 6         Simplify

h = -36 + 37.5 + 6                  Add all terms

h = 7.5 feet

 

The final answer is that the ball is 7.5 feet above the ground after 1.5 seconds.