Eric C. answered 02/24/16
Tutor
5.0
(180)
Engineer, Surfer Dude, Football Player, USC Alum, Math Aficionado
Hi Joanna.
For a polynomial to have zeros of sqrt(2) and i, it must also have a zero of -i, since complex zeros always travel as conjugates.
You would start by writing this:
P(x) = (x - √(2))*(x - i)*(x + i)
In this case, all of the above values of x result in P(x) = 0
This polynomial then becomes:
P(x) = (x - √(2))*(x^2 + 1)
Which then becomes
P(x) = x^3 - √(2)*x^2 + x - √(2)
This is the simplest polynomial with the given zeros.
Hope this helps.