
Tim T. answered 07/30/20
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Hey! Lets solve this shall we ?
So, we must find the point after making an initial translation from (x,y) to (x-1, y) then reflecting the point across the line x = 1. Let A'B'C' be the points after the translation. Then, let A"B"C" be the points after the reflection across the line x = 1. Thus,
A(0,0) => A'(-1, 0) => A"(3,0) [Since x = 1 is 2 units apart from (-1,0)].
B(1,3) => B'(0,3) => B"(2,3) [Since x = 1 is 1 unit apart from (1,3)}. Finally,
C(2,-4) => C'(1,-4) => C"(1,-4) [Since the translation point lies on line x = 1]. So the new triangle is
A"(3,0)B"(2,3)C"(1,-4)
I hope this helped!