Michael J. answered 02/22/16
Tutor
5
(5)
Mastery of Limits, Derivatives, and Integration Techniques
Assuming the function you have given is a result of several transformations, there is a parent function. The parent function is the reference function that you use to make the transformation. Notice the square-root part in the transformed function. This tells us that we started with a function that acts as a square-root function. So the parent function must be
y = √(x)
From this function, you would perform vertical shifts, horizontal shifts, and stretches to get the desired transformation.
EDIT:
After reviewing the function in detail, I noticed that this function can be rearranged so that it becomes a circle.
Subtract 2 on both sides of the equation.
y - 2 = √(25 - (x + 3)2)
Square both sides of the equation to undo the square-root.
(y - 2)2 = 25 - (x + 3)2
Add (x - 3)2 on both sides of the equation.
(x + 3)2 + (y - 2)2 = 25
Now you have a circle with a radius of 5 and centerpoint at (-3, 2).
The function you have given represents the upper half of the circle.