Equation relating stopping distance to velocity

Question

Driving on the Autobahn in Germany, you have to brake suddenly. Let’s assume that the stopping distance of a car varies directly as the square of the velocity of car when the brakes are applied. A car moving at 85 mph can stop in 367 feet.
a. Write an equation that relates the stopping distance to the velocity.
b. What is the stopping distance of your car if you were moving at 95 mph?

Answer 1

d =kv^2 = 367 = k85^2 = k7225

k = 367/7225

d= 367v^2/7225

going 95 mph the stopping distance d = 367(95^2)/85^2 = 367(19^2)/(17^2) = about 458.43 feet