Chemistry Equilibrium Problem? Calculate the partial pressure of a reactant? PLEASE HELP!??

Question

I am really stuck since I am new to equilibrium and would love if someone could show me how to solve this so I can learn!

 

For the reaction 4KO2(s) + 2H2O(g) ↔ 4KOH(s) + 3O2(g), an equilibrium mixture was found to contain 0.50atm of oxygen. Calculate the partial pressure of water vapor if KP = 1.25.

 

I think that Kp = P  O2^3 / P H2O^2, but I am not sure where to go from there.

Thanks for the help!!!!!

Answer 1

Well, Angelica, I'd say you are about 1 step from the answer. Your equation is correct, as the equilibrium constant only includes gases and solutions (and there are no solutions in this reaction). Just plug in the values for Kp and pO2 and solve for pH2O. Jim Scripko