Sanhita M. answered 02/03/16
Tutor
4.7
(11)
Mathematics and Geology
If cos x =1/4 then sec x = 4
tanx = ±√(sec2x-1) = ±√([secx]2-1) =±√([4]2-1) = ±√(16-1)=±√15
for 0≤x≤π/2, 0≤tanx≤∝ positive
for π≥x≥π/2, x≤∝0≤tanx≤∝ negative
for π≤x≤3π/2, 0≤tanx≤∝ positive
for 3π/2≥x≥2π, x≤∝0≤tanx≤∝ negative
As given cos x =1/4 is positive therefore either 0≤x≤π/2 or 3π/2≥x≥2π ,i.e., x lies either in first quadrant or in fourth quadrant.
Hence the solution, too is located either in first quadrant or in fourth quadrant.