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when working on the number line for divison does the divisor always repesent the hops? 5x3=15. therefore the4 number line would show 5 hops of 3?

Does the divisor always represent the hops in division? 5x3=15;Therefore you would se 5 hops of 3?

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First things first, a divisor isn't part of multiplication. It's a number that divides another number, N, without leaving a remainder. For instance, if we take 15/3 then 3 is the divisor because it divides 15 without leaving a remainder. 

Now to what you're asking, it's actually similar to a workout. When you're asked to do 5x10 jumps, it means you do 5 sets of 10 jumps. So if we apply that to here we can see that 5 is the number of times you will repeat 3 jumps and those 3 jumps are what you called a "hop". In this way you're making a 3 step "hop" 5 times. 

Hope this helped. =]


Two things:

  • It is not a requirement that a "divisor" leave no remainder.  Any number in the denominator can be called the "divisor" regardless of whether there is a remainder or not.
  • Since multiplication of real numbers is commutative, there is no special meaning attached to either the first number or the second number.  5x3 is the same as 3x5.  3 hops of 5 is the same as 5 hops of 3.

But if we're talking about it being applied to real life (which is closer to what was being asked) then the order does matter as I mentioned with workouts. Doing 5x10 push ups is different from 10x5. And yes, I do agree with that definition, some sources do define it without a remainer though.