Philip P. answered 02/01/16
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N = N0(1/2)t
Where:
- N = the number of coins left after "t" tosses
- N0 = the initial or starting number of coins
- t = tosses
What is the average half-life of 25 coins? 50 coins? 1 million coins?
N = N0(1/2)t
N/N0 = (1/2)t
For half-life, the ratio N/N0 = 1/2 regardless of the
number of coins you start with.
1/2 = (1/2)t
t = 1
For the second problem, with dimes and pennies, the number of coins you have is given by:
N = Np + Nd(1/2)t
Where:
- N = the number of coins left (dimes and pennies) after t tosses
- Np = the number of pennies, which doesn't change = 25
- Nd = the initial or starting number of dimes = 10
- t = tosses
N = Np + Nd(1/2)t
N = 25 + 10(1/2)t
Note that the number of pennies never changes, while the number of dimes gets cut in half with each toss. Can you finish from here?
Darrin C.
02/01/16