Idk how to do the parallel slope thing for geometry... One question is : through (2,3) parallel y=x+1

Question

through (2,3) parallel y=x+1

Answer 1

There is a problem with your problem as asked (see below), but I can walk you through the process of finding a parallel line given a slope and a point

 

The slope intercept form of an equation is y = mx + b.

 

You were given the equation y = x + 1, the slope is 1, it is not written because 1 is seldom written as a coefficient since x = 1x.  

 

Still this means your slope is 1.  A parallel line will have the same slope, m, and a different y-intercept, b.  

 

You can find the necessary b for your new equation by substituting your point's coordinates as the x and y of the equation.

 

(3) = m(2) + b     And as we have already seen your m = 1, so

3 = 2 + b

1 = b

 

So, your equation is y = x + 1, which is the equation you started with, so it's not really parallel, but identical.

 

Answer 2

A line is parallel to another line when they have the same slope.  The slope of the y = x+1 is 1.  

 

Using the point slope form, y-y1 = m(x-x1) [where m= the slope]; plug the point you are given into the equation with your slope of 1. 

 

        (y-3) = 1(x-2) 

 

Then you can solve to put your equation into this form: 

      y = x+5 . 

 

That is the equation for a line that is parallel to y- x+1 and has the point (2,3).