I am doing equivalent logarithms and would like to know how to simplify the following

log(x^2)-log(x)

I am doing equivalent logarithms and would like to know how to simplify the following

log(x^2)-log(x)

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log(x^2) - log(x) = log (x^2/x) = log x

log x

For the moment, think of log(x^2) as being log(x*x)

We know from the rules of logarithms that

log (x*y) = log(x) + log(y)

In this case, log(x^2)-log(x) = log(x) + log(x) - log(x) = **log(x)**