I am doing equivalent logarithms and would like to know how to simplify the following

log(x^2)-log(x)

I am doing equivalent logarithms and would like to know how to simplify the following

log(x^2)-log(x)

Tutors, please sign in to answer this question.

log(x^2) - log(x) = log (x^2/x) = log x

log x

For the moment, think of log(x^2) as being log(x*x)

We know from the rules of logarithms that

log (x*y) = log(x) + log(y)

In this case, log(x^2)-log(x) = log(x) + log(x) - log(x) = **log(x)**

Amaan M.

Math/Economics Teacher

New York, NY

5.0
(70 ratings)

Sean B.

Premier NYC Math tutor - young, passionate and talented

New York, NY

4.8
(30 ratings)

Rachalie B.

K-8 HW Helper & Math Tutor

Elmont, NY

4.9
(67 ratings)