Mary R. answered 01/08/16
Tutor
5.0
(248)
Experienced, Certified, Elementary/Special Ed Reading/Math Instructor
y = 3x - 2 ; x ≥ 0
In order to graph this linear equation, you must solve for y to determine (x,y) points on the graph.
You already know that x can equal or be more than 0, and that's a great starting place.
Draw a giant T and use whole numbers to substitute for x, beginning with 0. and solve for y
__X__l__Y__
0 l -2
1 l 1
2 l 4
1. Let x=0. Solve.
y = 3x - 2
y= 3(0) -2
y= 0 - 2
y= -2
Therefore, when x=0, y=-2
Plot these points (0, -2) with a solid point (not open)
The line begins here.
2. Let x=1. Solve.
y = 3x - 2
y = 3(1) -2
y= 3 - 2
y= 1
Therefore, when x= 1, y=1
Plot these points (1, 1)
Connect to the previous point and draw a line that continues indefinitely because x ≥ 0
3. Let x=2. Solve.
Lexi B.
01/08/16