Hi Nimo,
Since the actual diameter of the fire pit is 15m and the formula for the circumference is C = πd, substitute the circumference of 15m into the formula and solve for d.
15 = πd and then divide both sides by π getting d = 15/π = 5 rounded to the nearest meter. The scale drawing is smaller so (2/15) times 5 is 10/15 or 2/3 m
If the raised fire pit has a surface area of 6.47 and a similar one larger by a factor of 3 would have a surface area of
6.47 times 3 = 19.41 or 20m2 rounded to the nearest square meter.
For the last part, if the volume of the fire pit is .99m3 and the enlargement is 26.73m3, the scale factor used is
.99x = 26.73 ror x = 27
Nimo M.
Hi Mr. A.
For question c wouldn't the surface area be 58.23 meters squared.
Here is my work
scale factor = 3
SA of enlargement = SA of original x (scale factor)2
= 6.47 x (3)2
= 58.23 m2
Report
01/07/16
Nimo M.
For question d wouldn't the scale factor be 3
Here is my work
K3 = scale volume/ original volume
K3 = 26.73/0.99
3√k3 = 3√26.73/0.99
k = 3
the scale factor used was 3
Report
01/07/16
Nimo M.
01/07/16